`(n*(n + 1))/2`

), there's a formula for summation of squares, `(n/6)*(2n + 1)*(n + 1)`

, which suggests there's one for cubes, the 4th power, and the nth power as well, solve problem 6, project euler`Memory.hdl`

for nand2tetris! Working on the CPU now`/nocap-help`

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